5+3[1+2(2y-3)]+1=6(x+5)

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Solution for 5+3[1+2(2y-3)]+1=6(x+5) equation:


Simplifying
5 + 3[1 + 2(2y + -3)] + 1 = 6(x + 5)

Reorder the terms:
5 + 3[1 + 2(-3 + 2y)] + 1 = 6(x + 5)
5 + 3[1 + (-3 * 2 + 2y * 2)] + 1 = 6(x + 5)
5 + 3[1 + (-6 + 4y)] + 1 = 6(x + 5)

Combine like terms: 1 + -6 = -5
5 + 3[-5 + 4y] + 1 = 6(x + 5)
5 + [-5 * 3 + 4y * 3] + 1 = 6(x + 5)
5 + [-15 + 12y] + 1 = 6(x + 5)

Reorder the terms:
5 + -15 + 1 + 12y = 6(x + 5)

Combine like terms: 5 + -15 = -10
-10 + 1 + 12y = 6(x + 5)

Combine like terms: -10 + 1 = -9
-9 + 12y = 6(x + 5)

Reorder the terms:
-9 + 12y = 6(5 + x)
-9 + 12y = (5 * 6 + x * 6)
-9 + 12y = (30 + 6x)

Solving
-9 + 12y = 30 + 6x

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '9' to each side of the equation.
-9 + 9 + 12y = 30 + 9 + 6x

Combine like terms: -9 + 9 = 0
0 + 12y = 30 + 9 + 6x
12y = 30 + 9 + 6x

Combine like terms: 30 + 9 = 39
12y = 39 + 6x

Divide each side by '12'.
y = 3.25 + 0.5x

Simplifying
y = 3.25 + 0.5x

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